Use these equations to convert between the two systems. $$C = \frac { 5 } { 9 } ( F - 32 ) \quad F = \frac { 9 } { 5 } C + 32$$ Round answer to the nearest tenth of a degree if necessary.
-$$F = 5 ^ { \circ }$$
A) $\mathrm { C } = - 15 ^ { \circ }$
B) $C = - 0.8 ^ { \circ }$
C) $C = 20.6 ^ { \circ }$
D) $\mathrm { C } = - 48.6 ^ { \circ }$

Question

Quizplus · Accepted Answer

To convert $F = 5 ^ { \circ }$ to Celsius, use the formula $C = \frac { 5 } { 9 } ( F - 32 )$. Substituting $F = 5$, we get $C = \frac { 5 } { 9 } ( 5 - 32 ) = \frac { 5 } { 9 } ( -27 ) = -15 ^ { \circ }$.

Use These Equations to Convert Between the Two Systems C=59(F−32)F=95C+32C = \frac { 5 } { 9 } ( F - 32 ) \quad F = \frac { 9 } { 5 } C + 32C=95​(F−32)F=59​C+32

Use These Equations to Convert Between the Two Systems $C = \frac { 5 } { 9 } ( F - 32 ) \quad F = \frac { 9 } { 5 } C + 32$