Write the first n terms of the given arithmetic sequence (the value of n is indicated in the question).
-$$\mathrm { a } _ { 1 } = 3 - \sqrt { 7 } , \mathrm { a } _ { 2 } = 3 , \mathrm { n } = 4$$
A) $0,1 - \sqrt { 7 } , 4 - 4 \sqrt { 7 } , 5 - 5 \sqrt { 7 }$

B) $0,3 - \sqrt { 7 } , 3,3 + \sqrt { 7 }$

C) $3 - \sqrt { 7 } , 3,3 + \sqrt { 7 } , 3 + 2 \sqrt { 7 }$

D) $3 - \sqrt { 7 } , 4 - \sqrt { 7 } , 5 - \sqrt { 7 } , 6 - \sqrt { 7 }$

Question

Write the first n terms of the given arithmetic sequence (the value of n is indicated in the question).
-$$\mathrm { a } _ { 1 } = 3 - \sqrt { 7 } , \mathrm { a } _ { 2 } = 3 , \mathrm { n } = 4$$
A) $0,1 - \sqrt { 7 } , 4 - 4 \sqrt { 7 } , 5 - 5 \sqrt { 7 }$

B) $0,3 - \sqrt { 7 } , 3,3 + \sqrt { 7 }$

C) $3 - \sqrt { 7 } , 3,3 + \sqrt { 7 } , 3 + 2 \sqrt { 7 }$

D) $3 - \sqrt { 7 } , 4 - \sqrt { 7 } , 5 - \sqrt { 7 } , 6 - \sqrt { 7 }$

Quizplus · Accepted Answer

The common difference (d) can be found by subtracting the first term from the second term: $d = a_2 - a_1 = 3 - (3 - \sqrt{7}) = \sqrt{7}$. Thus, the sequence progresses by adding $\sqrt{7}$ to each term, making option C correct.

Write the First N Terms of the Given Arithmetic Sequence a1=3−7,a2=3,n=4\mathrm { a } _ { 1 } = 3 - \sqrt { 7 } , \mathrm { a } _ { 2 } = 3 , \mathrm { n } = 4a1​=3−7​,a2​=3,n=4

Write the First N Terms of the Given Arithmetic Sequence $\mathrm { a } _ { 1 } = 3 - \sqrt { 7 } , \mathrm { a } _ { 2 } = 3 , \mathrm { n } = 4$