Find the first six terms of the sequence.
-$a _ { 1 } = 8 , a _ { 2 } = 8 ;$ for $n \geq 3 , a _ { n } = a _ { n - 1 } + a _ { n - 2 }$
A) $8,8,16,16,24,24$
B) $8,8,16,24,40,64$
C) $8,8,64,512,32,768,16,777,216$
D) $8,8,16,24,32,40$

Question

Quizplus · Accepted Answer

The sequence starts with 8, 8 and each term thereafter is the sum of the two preceding terms. So, $a_3 = 8 + 8 = 16$, $a_4 = 8 + 16 = 24$, $a_5 = 16 + 24 = 40$, and $a_6 = 24 + 40 = 64$.

Find the First Six Terms of the Sequence a1=8,a2=8;a _ { 1 } = 8 , a _ { 2 } = 8 ;a1​=8,a2​=8;

Find the First Six Terms of the Sequence $a _ { 1 } = 8 , a _ { 2 } = 8 ;$