Find the center-radius form of the equation of the circle.
-center $( - \sqrt { 3 } , - 4 )$, radius $\sqrt { 3 }$
A) $( x + \sqrt { 3 } ) ^ { 2 } + ( y + 4 ) ^ { 2 } = 3$
B) $( x - \sqrt { 3 } ) ^ { 2 } + ( y - 4 ) ^ { 2 } = 9$
C) $( x + \sqrt { 3 } ) ^ { 2 } + ( y + 4 ) ^ { 2 } = \sqrt { 3 }$
D) $( x - \sqrt { 3 } ) ^ { 2 } + ( y - 4 ) ^ { 2 } = 3$

Question

Quizplus · Accepted Answer

The center-radius form of a circle is $(x - h)^2 + (y - k)^2 = r^2$, where $(h, k)$ is the center and $r$ is the radius. Substituting $h = -\sqrt{3}$, $k = -4$, and $r = \sqrt{3}$, we get $(x + \sqrt{3})^2 + (y + 4)^2 = (\sqrt{3})^2$, which simplifies to $(x + \sqrt{3})^2 + (y + 4)^2 = 3$.

Find the Center-Radius Form of the Equation of the Circle (−3,−4)( - \sqrt { 3 } , - 4 )(−3​,−4)

Find the Center-Radius Form of the Equation of the Circle $( - \sqrt { 3 } , - 4 )$