Round your answer to two decimal places.
-Hooke's Law for an elastic spring states that the distance a spring stretches varies directly as the force applied. If a force of 25 pounds stretches a certain spring 7 inches, then how much
Will a force of 75 pounds stretch the spring?
A) 3 in.
B) 175 in.
C) 2 in.
D) 21 in.

Question

Quizplus · Accepted Answer

Hooke's Law can be represented by the formula $F = kx$, where $F$ is the force applied, $x$ is the distance stretched, and $k$ is the spring constant. Given that 25 pounds stretches the spring 7 inches, we can find $k$ by rearranging the formula to $k = \frac{F}{x} = \frac{25}{7}$. To find how much a force of 75 pounds will stretch the spring, we use the formula with the found value of $k$: $75 = kx = \frac{25}{7}x$, solving for $x$ gives $x = \frac{75 \times 7}{25} = 21$ inches.

Round Your Answer to Two Decimal Places