Give the domain and range for the rational function. Use interval notation.
-$$f ( x ) = \frac { 1 } { x + 5 }$$
A) Domain: $( - \infty , - 5 ) \cup ( - 5 , \infty )$; Range: $( 0 , \infty )$
B) Domain: $( - \infty , 0 ) \cup ( 0 , \infty )$; Range: $( - \infty , - 5 ) \cup ( - 5 , \infty )$
C) Domain: $( - \infty , - 5 ) \cup ( - 5 , \infty )$; Range: $( - \infty , 0 ) \cup ( 0 , \infty )$
D) Domain: $( - \infty , 5 ) \cup ( 5 , \infty )$; Range: $( - \infty , 0 ) \cup ( 0 , \infty )$

Question

Quizplus · Accepted Answer

The function $\frac{1}{x+5}$ is undefined at $x = -5$, hence the domain excludes -5. The range of a rational function of this form excludes 0, as the function never equals 0 but can take any other real value.

Give the Domain and Range for the Rational Function f(x)=1x+5f ( x ) = \frac { 1 } { x + 5 }f(x)=x+51​

Give the Domain and Range for the Rational Function $f ( x ) = \frac { 1 } { x + 5 }$