Use Descartes' Rule of Signs to Determine the Possible Number $$f ( x ) = - 6 x ^ { 4 } - 8 x ^ { 3 } - 7 x ^ { 2 } - 8 x + 3$$

Use Descartes' Rule of Signs to determine the possible number of positive real zeros and the possible number of negative
real zeros for the function.
- $$f ( x ) = - 6 x ^ { 4 } - 8 x ^ { 3 } - 7 x ^ { 2 } - 8 x + 3$$

A)
$\begin{array}{c|c|c}\text { Positive } & \text { Negative } & \text { Nonreal Complex } \\\hline 2 & 2 & 0 \\2 & 0 & 2 \\0 & 2 & 2 \\0 & 0 & 2\end{array}$

B)
$\begin{array}{c|c|c}\text { Positive } & \text { Negative } & \text { Nonreal Complex } \\\hline 1 & 1 & 2\end{array}$

C)
$\begin{array}{c|c|c}\text { Positive } & \text { Negative } & \text { Nonreal Complex } \\\hline 1 & 2 & 1\end{array}$

D)
$\begin{array}{c|c|c}\text { Positive } & \text { Negative } & \text { Nonreal Complex } \\\hline 1 & 3 & 0 \\1 & 1 & 2\end{array}$