Solve the inequality. Write the solution set in interval notation.
-$$x ^ { 2 } + 3 x - 18

Question

Solve the inequality. Write the solution set in interval notation.
-$$x ^ { 2 } + 3 x - 18 < 0$$
A) $( - 6,3 )$
B) $( \infty , - 6 ) \cup ( 3 , \infty )$
C) $( \infty , - 3 ) \cup ( 6 , \infty )$
D) $( - 3,6 )$

Quizplus · Accepted Answer

First, factor the quadratic inequality: $x^2 + 3x - 18 < 0$ becomes $(x + 6)(x - 3) < 0$. The roots are $x = -6$ and $x = 3$. The inequality is satisfied between these two roots, so the solution set in interval notation is $(-6, 3)$.

Solve the Inequality x2+3x−18<0x ^ { 2 } + 3 x - 18 < 0x2+3x−18<0

Solve the Inequality $x ^ { 2 } + 3 x - 18 < 0$