Solve the Problem
-If an Object Is Thrown Upward with an Initial

Solve the problem
-If an object is thrown upward with an initial velocity of $48 \mathrm { ft } / \mathrm { sec }$ , its height after $\mathrm { t }$ sec is given by $\mathrm { s } ( \mathrm { t } ) = 48 \mathrm { t } - 16 \mathrm { t } ^ { 2 }$ . Find the maximum height attained by the object. (The object will attain maximum height exactly at the halfway point in terms of the time $t$ , where $t = 0$ is at the beginning of the object's flight, and the final time is when the object hits the ground.)

A) $48 \mathrm { ft }$
B) $36 \mathrm { ft }$
C) $32 \mathrm { ft }$
D) $20 \mathrm { ft }$