Solve the problem
-If an object is propelled upward from a height of 96 feet at an initial velocity of 64 feet per second, then its height after $t$ seconds is given by the equation $h ( t ) = - 16 t ^ { 2 } + 64 t + 96$, where height is in feet. After how many seconds will the object reach a height of 160 feet?
A) $2 \mathrm { sec }$
B) $1 \mathrm { sec }$
C) $8 \mathrm { sec }$
D) $4 \mathrm { sec }$

Question

Quizplus · Accepted Answer

To find when the object reaches 160 feet, substitute $h(t) = 160$ into the equation and solve for $t$: $160 = -16t^2 + 64t + 96$. Rearranging gives $0 = -16t^2 + 64t - 64$, which simplifies to $t^2 - 4t + 4 = 0$. Factoring yields $(t - 2)^2 = 0$, so $t = 2$ seconds.

Solve the Problem -If an Object Is Propelled Upward from a Height

Solve the Problem
-If an Object Is Propelled Upward from a Height