(8,-2) ; m=-$\frac { 4 } { 5 }$
A) y= $\frac { 4 } { 5 } x - \frac { 22 } { 5 }$
B) y=-$\frac { 4 } { 5 }$x+6
C) y= $= \frac { 4 } { 5 } x + \frac { 42 } { 5 }$
D) y= $- \frac { 4 } { 5 } x + \frac { 22 } { 5 }$

Question

(8,-2) ; m=-$\frac { 4 } { 5 }$
A)  y=  $\frac { 4 } { 5 } x - \frac { 22 } { 5 }$
B)  y=-$\frac { 4 } { 5 }$x+6 
C)  y=  $= \frac { 4 } { 5 } x + \frac { 42 } { 5 }$
D)  y=  $- \frac { 4 } { 5 } x + \frac { 22 } { 5 }$

Quizplus · Accepted Answer

To find the equation of the line with slope $m = -\frac{4}{5}$ passing through the point (8, -2), we use the point-slope form of a line equation: $y - y_1 = m(x - x_1)$, where $(x_1, y_1)$ is a point on the line. Substituting $m = -\frac{4}{5}$, $x_1 = 8$, and $y_1 = -2$, we get $y + 2 = -\frac{4}{5}(x - 8)$. Simplifying, $y = -\frac{4}{5}x + \frac{32}{5} - 2$, which simplifies further to $y = -\frac{4}{5}x + \frac{22}{5}$.

(8,-2) ; M=- 45\frac { 4 } { 5 }54​ A) Y=

(8,-2) ; M=- $\frac { 4 } { 5 }$ A) Y=