Solve the system of equations by substitution, if a solution exists.
-$$\left\{ \begin{array} { l }
- 6 x + 6 y = 66 \
- 3 x + 4 y = 42
\end{array} \right.$$
A) $x = - 3 , y = 10$
B) $x = - 2 , y = 10$
C) No solution
D) $x = - 2 , y = 9$

Question

Solve the system of equations by substitution, if a solution exists.
-$$\left\{ \begin{array} { l } 
- 6 x + 6 y = 66 \
- 3 x + 4 y = 42
\end{array} \right.$$
A) $x = - 3 , y = 10$
B) $x = - 2 , y = 10$
C) No solution
D) $x = - 2 , y = 9$

Quizplus · Accepted Answer

The Answer of Solve the system of equations by substitution, if a solution exists.
-$$\left\{ \begin{array} { l } 
- 6 x + 6 y = 66 \
- 3 x + 4 y = 42
\end{array} \right.$$
A) $x = - 3 , y = 10$
B) $x = - 2 , y = 10$
C) No solution
D) $x = - 2 , y = 9$

Solve the System of Equations by Substitution, If a Solution {−6x+6y=66−3x+4y=42\left\{ \begin{array} { l } - 6 x + 6 y = 66 \\- 3 x + 4 y = 42\end{array} \right.{−6x+6y=66−3x+4y=42​

Solve the System of Equations by Substitution, If a Solution $\left\{ \begin{array} { l } - 6 x + 6 y = 66 \\- 3 x + 4 y = 42\end{array} \right.$