The Height H of a Ball Thrown Is $h ( x ) = 2 x - 0.08 x ^ { 2 }$

The height h of a ball thrown is given by $h ( x ) = 2 x - 0.08 x ^ { 2 }$ where x is the horizontal distance traveled and both measurements are in feet. At what horizontal distances will the height of the ball be more than 9 ft ? (Round distances to the nearest tenth of a foot, if necessary.)

A) $0 \mathrm { ft } < \mathrm { x } < 5.9 \mathrm { ft } \text { or } 19.1 \mathrm { ft } < \mathrm { x } < 25 \mathrm { ft }$
B) $0 \mathrm { ft } < \mathrm { x } < 19.1 \mathrm { ft }$
C) $5.9 \mathrm { ft } < \mathrm { x } < 25 \mathrm { ft }$
D) $5.9 \mathrm { ft } < \mathrm { x } < 19.1 \mathrm { ft }$