Determine whether the function is even, odd, or neither.
-$y = \sqrt { x ^ { 2 } + 5 }$
A) Odd
B) Neither
C) Even

Name: Determine whether the function is even, odd, or neither. -$y = \sqrt { x ^ { 2 } + 5 }$ A) Odd B) Neither C) Even
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Question

Quizplus · Accepted Answer

A function is even if $f(-x) = f(x)$ for all $x$ in the function's domain. For $y = \sqrt{x^2 + 5}$, replacing $x$ with $-x$ gives $\sqrt{(-x)^2 + 5} = \sqrt{x^2 + 5}$, which is the same as the original function. Therefore, the function is even.

Determine Whether the Function Is Even, Odd, or Neither y=x2+5y = \sqrt { x ^ { 2 } + 5 }y=x2+5​

Determine Whether the Function Is Even, Odd, or Neither $y = \sqrt { x ^ { 2 } + 5 }$