Evaluate the function. Round to two decimal places.
-Evaluate $\frac { 64 } { 1 + 0.2 e ^ { - 0.06 x } } \text { when } x = 18$
A) 77.91
B) 149.82
C) 41.95
D) 59.93

Question

Quizplus · Accepted Answer

The function given is $\frac { 64 } { 1 + 0.2 e ^ { - 0.06 x } }$. To evaluate it when $x = 18$, we substitute 18 for $x$ and calculate:$$\frac { 64 } { 1 + 0.2 e ^ { - 0.06 \times 18 } } = \frac { 64 } { 1 + 0.2 e ^ { -1.08 } }$$Calculating the exponent part:$$e^{-1.08} \approx 0.339322$$Then, the entire denominator becomes:$$1 + 0.2 \times 0.339322 \approx 1.0678644$$Finally, dividing 64 by this value gives:$$\frac { 64 } { 1.0678644 } \approx 59.93$$Therefore, the correct answer is 59.93, which corresponds to choice D.

Evaluate the Function 641+0.2e−0.06x when x=18\frac { 64 } { 1 + 0.2 e ^ { - 0.06 x } } \text { when } x = 181+0.2e−0.06x64​ when x=18

Evaluate the Function $\frac { 64 } { 1 + 0.2 e ^ { - 0.06 x } } \text { when } x = 18$