Multiply using the rule for finding the product of the sum and difference of two terms.
-$$\left( 3 x + \frac { 1 } { 3 } \right) \left( 3 x - \frac { 1 } { 3 } \right)$$
A) $9 x ^ { 2 } - \frac { 2 } { 3 } x + \frac { 1 } { 9 }$
B) $9 x ^ { 2 } - \frac { 2 } { 3 }$
C) $9 x ^ { 2 } - \frac { 2 } { 3 } x - \frac { 1 } { 9 }$
D) $9 x ^ { 2 } - \frac { 1 } { 9 }$

Question

Quizplus · Accepted Answer

The product of the sum and difference of two terms is given by the formula $a^2 - b^2$. Applying this to the given expression, we get $(3x)^2 - \left(\frac{1}{3}\right)^2 = 9x^2 - \frac{1}{9}$.

Multiply Using the Rule for Finding the Product of the Sum