Factor by grouping.
-$x ^ { 2 } - 4 x - 3 x + 12$
A) $( x - 3 ) ( x + 8 )$
B) $( x + 3 ) ( x - 4 )$
C) $- 7 x \left( x ^ { 2 } + 12 \right)$
D) $( x - 3 ) ( x - 4 )$

Question

Quizplus · Accepted Answer

The expression can be grouped and factored as follows: $x^2 - 4x - 3x + 12 = (x^2 - 4x) - (3x - 12)$. Factoring out the common terms gives $x(x - 4) - 3(x - 4)$, which can be further factored into $(x - 3)(x - 4)$.

Factor by Grouping x2−4x−3x+12x ^ { 2 } - 4 x - 3 x + 12x2−4x−3x+12

Factor by Grouping $x ^ { 2 } - 4 x - 3 x + 12$