A city has been growing at a rate of 0.5% annually. If there are currently 4,457,000 residents in the city, how many (to the nearest ten-thousand) would be living in this city six years from now? Use the function $$f ( x ) = 4,457,000 ( 2.7 ) ^ { 0.005 t }$$
A) 4,620,000
B) 4,590,000
C) 360,000
D) 12,030,000

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The Answer of A city has been growing at a rate of 0.5% annually. If there are currently 4,457,000 residents in the city, how many (to the nearest ten-thousand) would be living in this city six years from now? Use the function $$f ( x ) = 4,457,000 ( 2.7 ) ^ { 0.005 t }$$
A) 4,620,000
B) 4,590,000
C) 360,000
D) 12,030,000

A City Has Been Growing at a Rate of 0 f(x)=4,457,000(2.7)0.005tf ( x ) = 4,457,000 ( 2.7 ) ^ { 0.005 t }f(x)=4,457,000(2.7)0.005t

A City Has Been Growing at a Rate of 0 $f ( x ) = 4,457,000 ( 2.7 ) ^ { 0.005 t }$