Solve the problem.
-Use $\log _ { b } 2 \approx 0.333$ and $\log _ { b } 6 \approx 0.862$ to approximate the value of the given logarithm. $\log _ { b } 12$
A) $2.589$
B) $0.287$
C) $1.195$
D) $0.529$

Question

Quizplus · Accepted Answer

Using the properties of logarithms, $\log_b 12$ can be rewritten as $\log_b (2 \cdot 6)$, which simplifies to $\log_b 2 + \log_b 6$. Using the given approximations, this equals $0.333 + 0.862 = 1.195$.

Solve the Problem log⁡b2≈0.333\log _ { b } 2 \approx 0.333logb​2≈0.333

Solve the Problem $\log _ { b } 2 \approx 0.333$