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Solve the Problem A0A _ { 0 } Of the Drug in the Bloodstream at the Time of Treats

Question 146

Multiple Choice

Solve the problem.
-The attending physician in an emergency room treats an unconscious patient suspected of a drug overdose. The physician does not know the initial concentration A0A _ { 0 } of the drug in the bloodstream at the time of injection. However, the physician knows that after 3hr3 \mathrm { hr } , the drug concentration in the blood is 0.75μg/dL0.75 \mu \mathrm { g } / \mathrm { dL } and after 4hr4 \mathrm { hr } , the concentration is 0.719μg/dL0.719 \mu \mathrm { g } / \mathrm { dL } . The model A(t) =A0ektA ( t ) = A _ { 0 } \mathrm { e } ^ { - k t } represents the drug concentration A(t) A ( t ) (in μg/dL) \mu \mathrm { g } / \mathrm { dL } ) in the bloodstream tt hours after injection. The value of kk is a constant related to the rate at which the drug is removed by the body.


A) a. 0.75=A0e3t0.75 = A _ { 0 } \mathrm { e } ^ { 3 t }
b. 0.719=A0e4t0.719 = A _ { 0 } \mathrm { e } ^ { 4 t }
c. k=0.042k = 0.042
B) a. 0.75=A0e3t0.75 = A _ { 0 } \mathrm { e } ^ { - 3 t }
b. 0.719=A0e4t0.719 = A _ { 0 } \mathrm { e } ^ { - 4 t }
c. k=0.618k = 0.618
C) a. 0.75=A0e3t0.75 = A _ { 0 } \mathrm { e } ^ { - 3 t }
b. 0.719=A0e4t0.719 = A _ { 0 } \mathrm { e } ^ { - 4 t }
c. k=0.042k = 0.042
D) a. 0.75=A0e3t0.75 = A _ { 0 } \mathrm { e } ^ { 3 t }
b. 0.719=A0e4t0.719 = A _ { 0 } \mathrm { e } ^ { 4 t }
c. k=0.618k = 0.618

Correct Answer:

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