Solve the problem.
-Suppose that a jury pool consists of 19 women and 20 men.
a. What is the probability that a jury of 7 people taken at random from the pool will consist only of
Women?
b. What is the probability that the jury will consist only of men?
A) a. $\approx 0.51282 ;$ b. $\approx 0.00504$
B) $\mathbf { a } . \approx 0.00328 ;$ b. $\approx 0.00504$
C) a. $\approx 0.01842 ;$ b. $\approx 0.01842$
D) $\mathbf { a } . \approx 0.51282 ;$ b. $\approx 0.01842$

Question

Solve the problem.
-Suppose that a jury pool consists of 19 women and 20 men. 
a. What is the probability that a jury of 7 people taken at random from the pool will consist only of
Women?
b. What is the probability that the jury will consist only of men? 
A) a. $\approx 0.51282 ;$ b. $\approx 0.00504$
B) $\mathbf { a } . \approx 0.00328 ;$ b. $\approx 0.00504$
C) a. $\approx 0.01842 ;$ b. $\approx 0.01842$
D) $\mathbf { a } . \approx 0.51282 ;$ b. $\approx 0.01842$

Quizplus · Accepted Answer

For a, the probability is calculated using combinations: $P(\text{7 women}) = \frac{{\binom{19}{7}}}{{\binom{39}{7}}}$, which approximates to 0.00328. For b, it's $P(\text{7 men}) = \frac{{\binom{20}{7}}}{{\binom{39}{7}}}$, approximating to 0.00504.

Solve the Problem ≈0.51282;\approx 0.51282 ;≈0.51282; B ≈0.00504\approx 0.00504≈0.00504 B) a.≈0.00328;\mathbf { a } . \approx 0.00328 ;a.≈0.00328;

Solve the Problem $\approx 0.51282 ;$ B $\approx 0.00504$ B) $\mathbf { a } . \approx 0.00328 ;$