Fill in the missing entries in the following partially completed one -way ANOVA table._ $\begin{array}{l|c|c|c|c}
\text { Source } & d f & S S & M S=S S / d f & F \text {-statistic } \
\hline \text { Treatment } & 3 & & & 11.16 \
\hline \text { Error } & & 13.72 & 0.686 & \
\hline \text { Total } & & & &
\end{array}$

A)
$\begin{array}{l|c|c|c|c}
\text { Source } & d f & S S & M S=S S / d f & F \text {-statistic } \
\hline \text { Treatment } & 3 & 22.97 & 7.66 & 11.16 \
\hline \text { Error } & 20 & 13.72 & 0.686 & \
\hline \text { Total } & 23 & 36.69 & &
\end{array}$

B) $\begin{array}{l|c|c|c|c}
\text { Source } & \boldsymbol{d f} & \boldsymbol{S S} & \boldsymbol{M S}=\boldsymbol{S S} / d \boldsymbol{f} & \boldsymbol{F} \text {-statistic } \
\hline \text { Treatment } & 3 & 2.55 & 7.66 & 11.16 \
\hline \text { Error } & 20 & 13.72 & 0.686 & \
\hline \text { Total } & 23 & 16.27 & &
\end{array}$

C) $\begin{array}{l|c|c|c|c}
\text { Source } & \boldsymbol{d f} & \boldsymbol{S S} & \boldsymbol{M S}=\boldsymbol{S S} / \mathrm{df} & \boldsymbol{F} \text {-statistic } \
\hline \text { Treatment } & 3 & 48.80 & 16.27 & 11.16 \
\hline \text { Error } & 20 & 13.72 & 0.686 & \
\hline \text { Total } & 23 & 62.52 & &
\end{array}$

D) $\begin{array}{l|c|c|c|c}
\text { Source } & \boldsymbol{d} \boldsymbol{f} & \boldsymbol{S S} & \boldsymbol{M S}=\boldsymbol{S S} / \mathrm{df} & \boldsymbol{F} \text {-statistic } \
\hline \text { Treatment } & 3 & 0.184 & 0.061 & 11.16 \
\hline \text { Error } & 20 & 13.72 & 0.686 & \
\hline \text { Total } & 23 & 13.90 & &
\end{array}$

Question

Fill in the missing entries in the following partially completed one -way ANOVA table._ $\begin{array}{l|c|c|c|c}
\text { Source } & d f & S S & M S=S S / d f & F \text {-statistic } \
\hline \text { Treatment } & 3 & & & 11.16 \
\hline \text { Error } & & 13.72 & 0.686 & \
\hline \text { Total } & & & &
\end{array}$

A) 
$\begin{array}{l|c|c|c|c}
\text { Source } & d f & S S & M S=S S / d f & F \text {-statistic } \
\hline \text { Treatment } & 3 & 22.97 & 7.66 & 11.16 \
\hline \text { Error } & 20 & 13.72 & 0.686 & \
\hline \text { Total } & 23 & 36.69 & &
\end{array}$

B) $\begin{array}{l|c|c|c|c}
\text { Source } & \boldsymbol{d f} & \boldsymbol{S S} & \boldsymbol{M S}=\boldsymbol{S S} / d \boldsymbol{f} & \boldsymbol{F} \text {-statistic } \
\hline \text { Treatment } & 3 & 2.55 & 7.66 & 11.16 \
\hline \text { Error } & 20 & 13.72 & 0.686 & \
\hline \text { Total } & 23 & 16.27 & &
\end{array}$

C) $\begin{array}{l|c|c|c|c}
\text { Source } & \boldsymbol{d f} & \boldsymbol{S S} & \boldsymbol{M S}=\boldsymbol{S S} / \mathrm{df} & \boldsymbol{F} \text {-statistic } \
\hline \text { Treatment } & 3 & 48.80 & 16.27 & 11.16 \
\hline \text { Error } & 20 & 13.72 & 0.686 & \
\hline \text { Total } & 23 & 62.52 & &
\end{array}$

D) $\begin{array}{l|c|c|c|c}
\text { Source } & \boldsymbol{d} \boldsymbol{f} & \boldsymbol{S S} & \boldsymbol{M S}=\boldsymbol{S S} / \mathrm{df} & \boldsymbol{F} \text {-statistic } \
\hline \text { Treatment } & 3 & 0.184 & 0.061 & 11.16 \
\hline \text { Error } & 20 & 13.72 & 0.686 & \
\hline \text { Total } & 23 & 13.90 & &
\end{array}$

Quizplus · Accepted Answer

The correct choice is A because it correctly calculates the missing entries based on the given information. The treatment sum of squares (SS) is found by multiplying the mean square (MS) by the degrees of freedom (df), which gives 22.97 when using the F-statistic formula $F = MS_{\text{Treatment}} / MS_{\text{Error}}$. The error df is calculated as the total number of observations minus the number of groups, leading to 20. The total SS is the sum of the treatment and error SS, giving 36.69, and the total df is the sum of the treatment and error df, resulting in 23.

Fill in the Missing Entries in the Following Partially Completed