Solve.
-A rectangular holding pen for sheep is to be designed so that its perimeter is 30 meters and its area is 54 square meters. Find the dimensions of the holding pen.
A) $5 \mathrm {~m}$ by $10 \mathrm {~m}$
B) $5 \mathrm {~m}$ by $8 \mathrm {~m}$
C) $7 \mathrm {~m}$ by $8 \mathrm {~m}$
D) $6 \mathrm {~m}$ by $9 \mathrm {~m}$

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Quizplus · Accepted Answer

The dimensions that satisfy both the perimeter and area conditions are $6 \mathrm {~m}$ by $9 \mathrm {~m}$. The perimeter of a rectangle is given by $2l + 2w = 30$ and the area by $lw = 54$. Solving these equations simultaneously, we find that the dimensions that meet these criteria are $6 \mathrm {~m}$ by $9 \mathrm {~m}$.

Solve -A Rectangular Holding Pen for Sheep Is to Be 5 m5 \mathrm {~m}5 m

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-A Rectangular Holding Pen for Sheep Is to Be $5 \mathrm {~m}$