The Graph of the Equation Is a Circle $x^{2}+y^{2}+6 x+6 y+14=0$

The graph of the equation is a circle. Find the center and the radius, and then graph the circle.
- $x^{2}+y^{2}+6 x+6 y+14=0$

A) center $( - 3,3 )$ ; radius $= 2$

B) center $( 3,3 )$ ; radius $= 2$

C) center $( 3 , - 3 )$ ; radius $= 2$

D) center $( - 3 , - 3 )$ ; radius $= 2$