Solve the equation for the specified variable.
-$C = \frac { 5 } { 9 } ( F - 32 ) \text { for } F$
A) $F = \frac { 9 } { 5 } C + 32$
B) $\mathrm { F } = \frac { 9 } { 5 } \mathrm {~F} - 32$
C) $F = \frac { 5 } { 9 } C + 32$
D) $F = \frac { 5 } { 9 } F - 32$

Question

Quizplus · Accepted Answer

To solve for $F$, multiply both sides by $\frac{9}{5}$ and then add 32 to isolate $F$, resulting in $F = \frac{9}{5}C + 32$.

Solve the Equation for the Specified Variable C=59(F−32) for FC = \frac { 5 } { 9 } ( F - 32 ) \text { for } FC=95​(F−32) for F

Solve the Equation for the Specified Variable $C = \frac { 5 } { 9 } ( F - 32 ) \text { for } F$