Solve the compound inequality. Give the answer in interval notation.
-$9 x - 6

Question

Solve the compound inequality. Give the answer in interval notation.
-$9 x - 6 < 3 x \text { or } - 3 x \leq - 9$
A)  [1,3] 
B) $( - \infty , 1 ) \cup [ 3 , \infty )$
C)  (1,3) 
D)  $Q$

Quizplus · Accepted Answer

First, solve each inequality separately. For $9x - 6 < 3x$, subtract $3x$ from both sides to get $6x - 6 < 0$, then add 6 to both sides to get $6x < 6$, and divide by 6 to find $x < 1$. For $-3x \leq -9$, divide both sides by $-3$ (remember to flip the inequality sign when dividing by a negative) to get $x \geq 3$. Combining these gives the solution $(-\infty, 1) \cup [3, \infty)$.

Solve the Compound Inequality 9x−6<3x or −3x≤−99 x - 6 < 3 x \text { or } - 3 x \leq - 99x−6<3x or −3x≤−9

Solve the Compound Inequality $9 x - 6 < 3 x \text { or } - 3 x \leq - 9$