Solve the equation for the specified variable.
-$S = 2 \pi r h + 2 \pi r ^ { 2 }$ for h
A) $h = 2 \pi ( S - r )$
B) h=S-r
C) $h = \frac { S } { 2 \pi r } - 1$
D) $h = \frac { S - 2 \pi r ^ { 2 } } { 2 \pi r }$

Question

Solve the equation for the specified variable.
-$S = 2 \pi r h + 2 \pi r ^ { 2 }$ for h
A) $h = 2 \pi ( S - r )$
B)  h=S-r 
C) $h = \frac { S } { 2 \pi r } - 1$
D) $h = \frac { S - 2 \pi r ^ { 2 } } { 2 \pi r }$

Quizplus · Accepted Answer

To solve for $h$, we start with the given equation $S = 2 \pi r h + 2 \pi r^2$. We want to isolate $h$, so we subtract $2 \pi r^2$ from both sides to get $S - 2 \pi r^2 = 2 \pi r h$. Then, we divide both sides by $2 \pi r$ to isolate $h$, resulting in $h = \frac{S - 2 \pi r^2}{2 \pi r}$.

Solve the Equation for the Specified Variable S=2πrh+2πr2S = 2 \pi r h + 2 \pi r ^ { 2 }S=2πrh+2πr2

Solve the Equation for the Specified Variable $S = 2 \pi r h + 2 \pi r ^ { 2 }$