Solve the equation for the specified variable.
-$A = \frac { 1 } { 2 } h ( B + b )$ for b
A) $b = \frac { 2 A - B h } { h }$
B) $b = \frac { A - B h } { h }$
C) $\mathrm { b } = \frac { 2 \mathrm {~A} + \mathrm { Bh } } { \mathrm { h } }$
D) b=2A-Bh

Question

Solve the equation for the specified variable.
-$A = \frac { 1 } { 2 } h ( B + b )$  for  b
A) $b = \frac { 2 A - B h } { h }$
B) $b = \frac { A - B h } { h }$
C) $\mathrm { b } = \frac { 2 \mathrm {~A} + \mathrm { Bh } } { \mathrm { h } }$
D)  b=2A-Bh

Quizplus · Accepted Answer

To solve for $b$, first multiply both sides by 2 to get rid of the fraction: $2A = h(B + b)$. Then, isolate $b$ by subtracting $Bh$ from both sides: $2A - Bh = hb$. Finally, divide both sides by $h$ to solve for $b$, resulting in $b = \frac{2A - Bh}{h}$.

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Solve the Equation for the Specified Variable $A = \frac { 1 } { 2 } h ( B + b )$