Solve the system.
-$\int 4 x + y - \frac { 2 } { 3 } z = 29$
$\left\{ \frac { 1 } { 3 } x - 2 z = 8 \right.$
$x + 2 y = 12$
A) $( - 9,4 , - 2 )$
B) $( 4 , - 3 , - 6 )$
C) $( 6,3 , - 3 )$
D) $( 4,4 , - 3 )$

Question

Quizplus · Accepted Answer

To solve the system of equations, we can use substitution or elimination methods. The given system is:1) $4x + y - \frac{2}{3}z = 29$2) $\frac{1}{3}x - 2z = 8$3) $x + 2y = 12$First, solve equation 3 for $x$: $x = 12 - 2y$.Then, substitute $x$ in equation 1 and 2 to find $y$ and $z$. After finding $y$, substitute back to find $x$ and $z$. After solving, you'll find that the solution that fits all three equations is $x = 6$, $y = 3$, and $z = -3$, which corresponds to choice C $(6, 3, -3)$.

Solve the System ∫4x+y−23z=29\int 4 x + y - \frac { 2 } { 3 } z = 29∫4x+y−32​z=29

Solve the System $\int 4 x + y - \frac { 2 } { 3 } z = 29$