Multiply.
-$12 a b ^ { 2 } \left( 11 a ^ { 2 } b ^ { 3 } + 3 a b \right)$
A) $132 a ^ { 2 } b ^ { 5 } + 36 a ^ { 2 } b ^ { 3 }$
B) $132 a ^ { 3 } b ^ { 5 } + 36 a ^ { 2 } b ^ { 3 }$
C) $132 a ^ { 3 } b ^ { 4 } + 36 a ^ { 2 } b ^ { 3 }$
D) $132 a ^ { 3 } b ^ { 5 } + 36 a ^ { 2 } b ^ { 2 }$

Question

Quizplus · Accepted Answer

To solve this, distribute $12ab^2$ across the terms inside the parentheses. For the first term, $12ab^2 \times 11a^2b^3 = 132a^{(1+2)}b^{(2+3)} = 132a^3b^5$. For the second term, $12ab^2 \times 3ab = 36a^{(1+1)}b^{(2+1)} = 36a^2b^3$. Therefore, the correct answer is $132a^3b^5 + 36a^2b^3$.

Multiply - 12ab2(11a2b3+3ab)12 a b ^ { 2 } \left( 11 a ^ { 2 } b ^ { 3 } + 3 a b \right)12ab2(11a2b3+3ab)

Multiply
- $12 a b ^ { 2 } \left( 11 a ^ { 2 } b ^ { 3 } + 3 a b \right)$