Solve.
-A rocket is launched from the top of a cliff that is 48 feet high with an initial velocity of 120 feet per second. The height, $h$, of the rocket after $t$ seconds is given by the equation $h = - 16 t ^ { 2 } + 120 t + 48$. How long after the rocket is launched will it strike the ground? Round to the nearest tenth of a second, if necessary.
A) $9.1 \mathrm { sec }$
B) $8.5 \mathrm { sec }$
C) $7.9 \mathrm { sec }$
D) $9.5 \mathrm { sec }$

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The Answer of Solve.
-A rocket is launched from the top of a cliff that is 48 feet high with an initial velocity of 120 feet per second. The height, $h$, of the rocket after $t$ seconds is given by the equation $h = - 16 t ^ { 2 } + 120 t + 48$. How long after the rocket is launched will it strike the ground? Round to the nearest tenth of a second, if necessary.
A) $9.1 \mathrm { sec }$
B) $8.5 \mathrm { sec }$
C) $7.9 \mathrm { sec }$
D) $9.5 \mathrm { sec }$

Solve -A Rocket Is Launched from the Top of a Cliff

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-A Rocket Is Launched from the Top of a Cliff