Solve.
-The area of a rectangular wall in a classroom is 396 square feet. Its length is 3 feet shorter than three times its width. Find the length and width of the wall of the classroom.
A) Width $= 12 \mathrm { ft }$; length $= 33 \mathrm { ft }$
B) Width $= 12 \mathrm { ft }$; length $= 21 \mathrm { ft }$
C) Width $= 12 \mathrm { ft }$; length $= 39 \mathrm { ft }$
D) Width $= 12 \mathrm { ft }$; length $= 15 \mathrm { ft }$

Question

Quizplus · Accepted Answer

The correct equation based on the given information is $ \text{Area} = \text{length} \times \text{width} = (3w - 3)w = 396 $. Solving this quadratic equation, we find that $ w = 12 $ ft. Substituting $ w = 12 $ ft into the length equation, $ \text{length} = 3(12) - 3 = 33 $ ft.

Solve -The Area of a Rectangular Wall in a Classroom =12ft= 12 \mathrm { ft }=12ft

Solve
-The Area of a Rectangular Wall in a Classroom $= 12 \mathrm { ft }$