The following output from MINITAB presents the results of a hypothesis test.
Test of mu $= 54$ vs. not $= 54$
The assumed standard deviation $7.0$

$\begin{array}{llccrl}
\mathrm{N} & \text { Mean } & \text { SE Mean } & 95 \% \mathrm{CI} & \mathrm{Z} & \mathrm{P} \
59 & 57.64 & 2.452752 & (52.8326067,62.4473933) & 3.994196 & 0.000065
\end{array}$

Do you reject $H _ { 0 }$ at the $\alpha = 0.05$ level?
A) No
B) Yes
C) There is not enough information to draw a conclusion.

Question

The following output from MINITAB presents the results of a hypothesis test.
Test of mu $= 54$ vs. not $= 54$
The assumed standard deviation $7.0$

$\begin{array}{llccrl}
\mathrm{N} & \text { Mean } & \text { SE Mean } & 95 \% \mathrm{CI} & \mathrm{Z} & \mathrm{P} \
59 & 57.64 & 2.452752 & (52.8326067,62.4473933) & 3.994196 & 0.000065
\end{array}$

Do you reject $H _ { 0 }$ at the $\alpha = 0.05$ level?
A) No
B) Yes
C) There is not enough information to draw a conclusion.

Quizplus · Accepted Answer

The p-value (0.000065) is less than the significance level ($\alpha = 0.05$), indicating that we reject the null hypothesis $H_0$.

The Following Output from MINITAB Presents the Results of a Hypothesis