Use the formulas $\sum_{k=1}^{n} k=\frac{n(n+1)}{2}$ and
$\sum_{k=1}^{n} k^{2}=\frac{n(n+1)(2 n+1)}{6}$ to find the sum in terms
of $\text { n. } \sum_{k=1}^{n}\left(3 k^{2}-5 k+7\right)$

Question

Use the formulas $\sum_{k=1}^{n} k=\frac{n(n+1)}{2}$  and
$\sum_{k=1}^{n} k^{2}=\frac{n(n+1)(2 n+1)}{6}$  to find the sum in terms
of $\text { n. } \sum_{k=1}^{n}\left(3 k^{2}-5 k+7\right)$

Quizplus · Accepted Answer

The Answer of Use the formulas $\sum_{k=1}^{n} k=\frac{n(n+1)}{2}$  and
$\sum_{k=1}^{n} k^{2}=\frac{n(n+1)(2 n+1)}{6}$  to find the sum in terms
of $\text { n. } \sum_{k=1}^{n}\left(3 k^{2}-5 k+7\right)$

Use the Formulas ∑k=1nk=n(n+1)2\sum_{k=1}^{n} k=\frac{n(n+1)}{2}∑k=1n​k=2n(n+1)​ And ∑k=1nk2=n(n+1)(2n+1)6\sum_{k=1}^{n} k^{2}=\frac{n(n+1)(2 n+1)}{6}∑k=1n​k2=6n(n+1)(2n+1)​ To Find the Sum in Terms Of

Use the Formulas $\sum_{k=1}^{n} k=\frac{n(n+1)}{2}$ And $\sum_{k=1}^{n} k^{2}=\frac{n(n+1)(2 n+1)}{6}$ To Find the Sum in Terms
Of