Use the given information to find the P -value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). With $H _ { 1 } : p \neq 0.377$ the test statistic is z=3.06 .
A) 0.0011 ; reject the null hypothesis
B) 0.0022 ; fail to reject the null hypothesis
C) 0.0022 ; reject the null hypothesis
D) 0.0011 ; fail to reject the null hypothesis

Question

Use the given information to find the  P -value. Also, use a  0.05  significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). With $H _ { 1 } : p \neq 0.377$ the test statistic is  z=3.06 .
A)  0.0011 ; reject the null hypothesis
B)  0.0022 ; fail to reject the null hypothesis
C)  0.0022 ; reject the null hypothesis
D)  0.0011 ; fail to reject the null hypothesis

Quizplus · Accepted Answer

The test statistic z=3.06 corresponds to a two-tailed test since $H_1: p \neq 0.377$. Looking up the value in a standard normal distribution table or using a calculator, the area in one tail for z=3.06 is approximately 0.0011. Since it's a two-tailed test, we double this value to get the p-value, which is approximately 0.0022. Since the p-value (0.0022) is less than the significance level (0.05), we reject the null hypothesis.

Use the Given Information to Find the P -Value H1:p≠0.377H _ { 1 } : p \neq 0.377H1​:p=0.377

Use the Given Information to Find the P -Value $H _ { 1 } : p \neq 0.377$