Factor using the trial and error method
-$$7 x ^ { 2 } + 11 x - 6$$
A) $( 7 x - 3 ) ( x + 2 )$
B) $( 7 x + 2 ) ( x - 3 )$
C) $( 7 x - 2 ) ( x + 3 )$
D) $( 7 x + 3 ) ( x - 2 )$

Name: Factor using the trial and error method -\[7 x ^ { 2 } + 11 x - 6\] A) $( 7 x - 3 ) ( x + 2 )$ B) $( 7 x + 2 ) ( x - 3 )$ C) $( 7 x - 2 ) ( x + 3 )$ D) $( 7 x + 3 ) ( x - 2 )$
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Question

Quizplus · Accepted Answer

The correct factorization is $(7x - 3)(x + 2)$. Expanding this gives $7x^2 + 14x - 3x - 6 = 7x^2 + 11x - 6$, which matches the original expression.

Factor Using the Trial and Error Method - 7x2+11x−67 x ^ { 2 } + 11 x - 67x2+11x−6

Factor Using the Trial and Error Method
- $7 x ^ { 2 } + 11 x - 6$