Find the zeros of the polynomial function
-$$f ( x ) = x ^ { 3 } + 5 x ^ { 2 } - x - 5$$
A) $x = 1 , x = - 5 , x = 5$
B) $x = - 5 , x = 5$
C) $x = 25$
D) $x = - 1 , x = 1 , x = - 5$

Question

Quizplus · Accepted Answer

To find the zeros of the polynomial $f(x) = x^3 + 5x^2 - x - 5$, we can attempt to factor it or use synthetic division. Factoring by grouping, we get $x^2(x + 5) - 1(x + 5) = (x^2 - 1)(x + 5) = (x - 1)(x + 1)(x + 5)$. Thus, the zeros are $x = -5, x = -1, x = 1$.

Find the Zeros of the Polynomial Function - f(x)=x3+5x2−x−5f ( x ) = x ^ { 3 } + 5 x ^ { 2 } - x - 5f(x)=x3+5x2−x−5

Find the Zeros of the Polynomial Function
- $f ( x ) = x ^ { 3 } + 5 x ^ { 2 } - x - 5$