Solve the system by the method of your choice. Identify systems with no solution and systems with infinitely many solutions, using set notation to express their solution sets.
-$$\begin{array} { l }
\frac { x } { 3 } + \frac { y } { 6 } = 1 \
\frac { x } { 4 } - \frac { y } { 8 } = 0
\end{array}$$
A) $\left\{ \left( 3 , \frac { 3 } { 2 } \right) \right\}$
B) $\left\{ \left( \frac { 3 } { 2 } , 3 \right) \right\}$
C) $\left\{ ( x , y ) \mid \frac { x } { 3 } + \frac { y } { 6 } = 1 \right\}$
D) $\varnothing$

Question

Solve the system by the method of your choice. Identify systems with no solution and systems with infinitely many solutions, using set notation to express their solution sets.
-$$\begin{array} { l } 
\frac { x } { 3 } + \frac { y } { 6 } = 1 \
\frac { x } { 4 } - \frac { y } { 8 } = 0
\end{array}$$
A) $\left\{ \left( 3 , \frac { 3 } { 2 } \right) \right\}$
B) $\left\{ \left( \frac { 3 } { 2 } , 3 \right) \right\}$
C) $\left\{ ( x , y ) \mid \frac { x } { 3 } + \frac { y } { 6 } = 1 \right\}$
D) $\varnothing$

Quizplus · Accepted Answer

The Answer of Solve the system by the method of your choice. Identify systems with no solution and systems with infinitely many solutions, using set notation to express their solution sets.
-$$\begin{array} { l } 
\frac { x } { 3 } + \frac { y } { 6 } = 1 \
\frac { x } { 4 } - \frac { y } { 8 } = 0
\end{array}$$
A) $\left\{ \left( 3 , \frac { 3 } { 2 } \right) \right\}$
B) $\left\{ \left( \frac { 3 } { 2 } , 3 \right) \right\}$
C) $\left\{ ( x , y ) \mid \frac { x } { 3 } + \frac { y } { 6 } = 1 \right\}$
D) $\varnothing$

Solve the System by the Method of Your Choice x3+y6=1x4−y8=0\begin{array} { l } \frac { x } { 3 } + \frac { y } { 6 } = 1 \\\frac { x } { 4 } - \frac { y } { 8 } = 0\end{array}3x​+6y​=14x​−8y​=0​

Solve the System by the Method of Your Choice $\begin{array} { l } \frac { x } { 3 } + \frac { y } { 6 } = 1 \\\frac { x } { 4 } - \frac { y } { 8 } = 0\end{array}$