Solve the system by the addition method.
-$$\begin{array} { l }
2 x + 20 y = - 144 \
11 x + 5 y = 48
\end{array}$$
A) $\{ ( 8 , - 8 ) \}$
B) $\{ ( - 5,8 ) \}$
C) $\{ ( 11 , - 11 ) \}$
D) $\{ ( - 8,8 ) \}$

Question

Solve the system by the addition method.
-$$\begin{array} { l } 
2 x + 20 y = - 144 \
11 x + 5 y = 48
\end{array}$$
A) $\{ ( 8 , - 8 ) \}$
B) $\{ ( - 5,8 ) \}$
C) $\{ ( 11 , - 11 ) \}$
D) $\{ ( - 8,8 ) \}$

Quizplus · Accepted Answer

By multiplying the first equation by 11 and the second by -2, we can eliminate $x$ and solve for $y$. Substituting back to find $x$, we get the solution $(8, -8)$.

Solve the System by the Addition Method 2x+20y=−14411x+5y=48\begin{array} { l } 2 x + 20 y = - 144 \\11 x + 5 y = 48\end{array}2x+20y=−14411x+5y=48​

Solve the System by the Addition Method $\begin{array} { l } 2 x + 20 y = - 144 \\11 x + 5 y = 48\end{array}$