If the effective voltage of an ac receptacle is 120 V, what is the peak-to-peak voltage?
A) 84.8 V
B) 169.7 V
C) 339.4 V
D) 240 V

Question

Quizplus · Accepted Answer

The peak voltage (V_peak) of an AC signal is related to its effective (or RMS) voltage (V_rms) by the formula V_peak = V_rms * sqrt(2). Therefore, for an effective voltage of 120 V, the peak voltage is 120V * sqrt(2) ≈ 169.7 V. Since the peak-to-peak voltage (V_pp) is twice the peak voltage, V_pp = 2 * 169.7 V ≈ 339.4 V.

If the Effective Voltage of an Ac Receptacle Is 120