-The circuit has measured values of VB = 2.2 V, VE = 1.5 V and VC = 11.5 V. Which of the following could account for these readings?
A) The 68 kΩ resistor is open.
B) The 10 kΩ resistor is open.
C) The 6.2 kΩ resistor is open.
D) The 1.1 kΩ resistor is open.
E) There is no fault. The circuit is functioning as it should.

Question

-The circuit has measured values of VB = 2.2 V, VE = 1.5 V and VC = 11.5 V. Which of the following could account for these readings?
A) The 68 kΩ resistor is open. 
B) The 10 kΩ resistor is open. 
C) The 6.2 kΩ resistor is open. 
D) The 1.1 kΩ resistor is open. 
E) There is no fault. The circuit is functioning as it should.

Quizplus · Accepted Answer

Given the voltages VB, VE, and VC, the circuit appears to be functioning correctly. The voltage difference between VB and VE suggests that the base-emitter junction is forward-biased (VB - VE = 0.7V, which is typical for silicon transistors), and the relatively high voltage at VC indicates that the collector is at a higher potential, as expected in a properly functioning transistor circuit. The absence of extreme or zero voltages suggests that there are no open resistors disrupting the circuit's operation.

-The Circuit Has Measured Values of VB = 2