An object released from rest on another planet requires one second to fall a distance of 6 meters. What is the acceleration in meters per second per second due to gravity on this planet?
A) 3
B) 12
C) 6
D) 15
E) none of these

Question

Quizplus · Accepted Answer

The formula for distance fallen under constant acceleration is $ d = \frac{1}{2} a t^2 $. Plugging in the values $ d = 6 $ meters and $ t = 1 $ second, we get $ 6 = \frac{1}{2} a (1)^2 $. Solving for $ a $, we find $ a = 12 $ m/s².

An Object Released from Rest on Another Planet Requires One