If $R ( \theta ) = \sqrt { \theta } \cos \left( \theta ^ { 6 } \right)$ , then $R ^ { \prime } ( \theta ) = \frac { 1 } { 2 \sqrt { \theta } } \cos \left( \theta ^ { 6 } \right) + \sqrt { \theta } \cdot 6 \theta ^ { 5 } \sin \left( \theta ^ { 6 } \right)$ .

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The Answer of If $R ( \theta ) = \sqrt { \theta } \cos \left( \theta ^ { 6 } \right)$ , then $R ^ { \prime } ( \theta ) = \frac { 1 } { 2 \sqrt { \theta } } \cos \left( \theta ^ { 6 } \right) + \sqrt { \theta } \cdot 6 \theta ^ { 5 } \sin \left( \theta ^ { 6 } \right)$ .

If R(θ)=θcos⁡(θ6)R ( \theta ) = \sqrt { \theta } \cos \left( \theta ^ { 6 } \right)R(θ)=θ​cos(θ6)

If $R ( \theta ) = \sqrt { \theta } \cos \left( \theta ^ { 6 } \right)$