If $f(x)=\frac{x}{2}+4$ and g(x)= x + 1, how do $\int_{8}^{12} f(x) d x$ and $\int_{8}^{12} g(x) d x$ compare? A) $\int_{8}^{12} f(x) d x$ $\int_{8}^{12} g(x) d x$ C) $\int_{8}^{12} f(x) d x$ = $\int_{8}^{12} g(x) d x$

Question

If $f(x)=\frac{x}{2}+4$ and g(x)= x + 1, how do $\int_{8}^{12} f(x) d x$ and $\int_{8}^{12} g(x) d x$ compare?
A) $\int_{8}^{12} f(x) d x$ < $\int_{8}^{12} g(x) d x$
B) $\int_{8}^{12} f(x) d x$ > $\int_{8}^{12} g(x) d x$
C) $\int_{8}^{12} f(x) d x$ = $\int_{8}^{12} g(x) d x$

Quizplus · Accepted Answer

The Answer of If $f(x)=\frac{x}{2}+4$ and g(x)= x + 1, how do $\int_{8}^{12} f(x) d x$ and $\int_{8}^{12} g(x) d x$ compare?
A) $\int_{8}^{12} f(x) d x$ < $\int_{8}^{12} g(x) d x$
B) $\int_{8}^{12} f(x) d x$ > $\int_{8}^{12} g(x) d x$
C) $\int_{8}^{12} f(x) d x$ = $\int_{8}^{12} g(x) d x$

If f(x)=x2+4f(x)=\frac{x}{2}+4f(x)=2x​+4 And G(x)= X + 1, How Do ∫812f(x)dx\int_{8}^{12} f(x) d x∫812​f(x)dx

If $f(x)=\frac{x}{2}+4$ And G(x)= X + 1, How Do $\int_{8}^{12} f(x) d x$