Find the first harmonic of the function $f(x)=$$\left\{\begin{array}{c}
-2 \
2
\end{array}\right.$ $\begin{array}{c}
-\pi

Question

Find the first harmonic of the function $f(x)=$$\left\{\begin{array}{c}
-2 \
2
\end{array}\right.$ $\begin{array}{c}
-\pi< \
0<
\end{array}$$\begin{array}{l}
x \leq 0 \
x \leq \pi
\end{array}$
  .
A) $-2+\frac{8}{\pi} \sin x$
B) $2-\frac{4}{\pi} \sin x$
C) $\frac{8}{\pi} \sin x$
D) $\frac{4}{\pi} \sin x$
E)0

Quizplus · Accepted Answer

The first harmonic of a square wave function with period $2\pi$ and amplitude difference of 4 is given by $\frac{8}{\pi} \sin x$.

Find the First Harmonic of the Function f(x)=f(x)=f(x)= {−22\left\{\begin{array}{c}-2 \\2\end{array}\right.{−22​ −π<0<\begin{array}{c}-\pi< \\0<\end{array}−π<0<​

Find the First Harmonic of the Function $f(x)=$ $\left\{\begin{array}{c}-2 \\2\end{array}\right.$ $\begin{array}{c}-\pi< \\0<\end{array}$