The equation $\vec { r } = 4 x \vec { i } + 4 y \vec { j } = 12 \cos ( 2 \pi / 360 ) \vec { i } + 12 \sin ( 2 \pi / 360 ) \vec { j }$ describes the motion of a particle moving on a circle.Assume x and y are in miles and t is in days.
What is the speed of the particle when it passes through the point (0, 2)?

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The Answer of The equation $\vec { r } = 4 x \vec { i } + 4 y \vec { j } = 12 \cos ( 2 \pi / 360 ) \vec { i } + 12 \sin ( 2 \pi / 360 ) \vec { j }$ describes the motion of a particle moving on a circle.Assume x and y are in miles and t is in days.
What is the speed of the particle when it passes through the point (0, 2)?

The Equation r⃗=4xi⃗+4yj⃗=12cos⁡(2π/360)i⃗+12sin⁡(2π/360)j⃗\vec { r } = 4 x \vec { i } + 4 y \vec { j } = 12 \cos ( 2 \pi / 360 ) \vec { i } + 12 \sin ( 2 \pi / 360 ) \vec { j }r=4xi+4yj​=12cos(2π/360)i+12sin(2π/360)j​

The Equation $\vec { r } = 4 x \vec { i } + 4 y \vec { j } = 12 \cos ( 2 \pi / 360 ) \vec { i } + 12 \sin ( 2 \pi / 360 ) \vec { j }$