A 0.100 m K₂SO₄ solution has a freezing point of -0.43$\degree$C. What is the van't Hoff factor for this solution? K_f = 1.86$\degree$C/m A) 0.77 B) 1.0 C) 2.3 D) 3.0 E) 3.0

Question

A 0.100 m K₂SO₄ solution has a freezing point of -0.43$\degree$C. What is the van't Hoff factor for this solution? K_f = 1.86$\degree$C/m A) 0.77 B) 1.0 C) 2.3 D) 3.0 E) >3.0

Quizplus · Accepted Answer

The van't Hoff factor (i) is given by:
i = (measured freezing point depression)/(theoretical freezing point depression)
The theoretical freezing point depression is calculated using the formula:
ΔTf = Kf * i * molality
where Kf is the freezing point depression constant for the solvent (in this case water), and molality is the number of moles of solute per kilogram of solvent.
Substituting the given values, we get:
-0.43 = 1.86 * i * 0.1
Solving for i, we get:
i = -0.43/(1.86 * 0.1) = 2.32
Rounding off to one decimal place gives i = 2.3.
Therefore, the answer is C, 2.3.

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