Solve the system of equations using the addition method: a + 3b = 13
A - 3b = -11
A) $a = 1 , b = 4$
B) $a = 2 , b = 3 \frac { 2 } { 3 }$
C) $a = 0 , b = 41 \frac { 1 } { 3 }$
D) $a = 10 , b = 1$

Question

Quizplus · Accepted Answer

Adding the two equations eliminates $b$, resulting in $2a = 2$, which simplifies to $a = 1$. Substituting $a = 1$ into the first equation gives $1 + 3b = 13$, leading to $b = 4$.

Solve the System of Equations Using the Addition Method: a a=1,b=4a = 1 , b = 4a=1,b=4

Solve the System of Equations Using the Addition Method: a $a = 1 , b = 4$