Since the mean of $\hat { \beta } _ { 1 } \text { is } E ( \hat { \beta }_{1} ) = \beta _ { 1 } \text {, then } \hat { \beta }_{1}$ is an __________ estimator of $\beta _ { 1 }$ .

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The Answer of Since the mean of $\hat { \beta } _ { 1 } \text { is } E ( \hat { \beta }_{1} ) = \beta _ { 1 } \text {, then } \hat { \beta }_{1}$ is an __________ estimator of $\beta _ { 1 }$ .

Since the Mean Of β^1 is E(β^1)=β1, then β^1\hat { \beta } _ { 1 } \text { is } E ( \hat { \beta }_{1} ) = \beta _ { 1 } \text {, then } \hat { \beta }_{1}β^​1​ is E(β^​1​)=β1​, then β^​1​

Since the Mean Of $\hat { \beta } _ { 1 } \text { is } E ( \hat { \beta }_{1} ) = \beta _ { 1 } \text {, then } \hat { \beta }_{1}$