In calculating 95% confidence interval for $\mu _ { 1 } - \mu _ { 2 } ;$ the difference between the means of two normally distributed populations, summary statistics from two independent samples are: $m = 60 , \bar { x } = 180 , s _ { 1 } ^ { 2 } = 360 , n = 45 , \bar { y } = 160 , \text { and } s _ { 2 } ^ { 2 } = 900$ Then, the lower limit of the confidence interval is:
A) 29.994
B) 11.587
C) 10.006
D) 10.797
E) 28.413

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The Answer of In calculating 95% confidence interval for $\mu _ { 1 } - \mu _ { 2 } ;$ the difference between the means of two normally distributed populations, summary statistics from two independent samples are: $m = 60 , \bar { x } = 180 , s _ { 1 } ^ { 2 } = 360 , n = 45 , \bar { y } = 160 , \text { and } s _ { 2 } ^ { 2 } = 900$ Then, the lower limit of the confidence interval is:
A) 29.994
B) 11.587
C) 10.006
D) 10.797
E) 28.413

In Calculating 95% Confidence Interval For μ1−μ2;\mu _ { 1 } - \mu _ { 2 } ;μ1​−μ2​;

In Calculating 95% Confidence Interval For $\mu _ { 1 } - \mu _ { 2 } ;$